125=(1/25)^x

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Solution for 125=(1/25)^x equation: 



125=(1/25)^x

We move all terms to the left:

125-((1/25)^x)=0



Domain of the equation: 25)^x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+1/25)^x)+125=0

We multiply all the terms by the denominator


-((+1+125*25)^x)=0



We calculate terms in parentheses: -((+1+125*25)^x), so:

(+1+125*25)^x

We add all the numbers together, and all the variables

3126^x

Back to the equation:

-(3126^x)



x=0/1

x=0

Równanie nie ma rozwiązania

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